x^2+2ix-(1+i)=0

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Solution for x^2+2ix-(1+i)=0 equation:


Simplifying
x2 + 2ix + -1(1 + i) = 0
x2 + 2ix + (1 * -1 + i * -1) = 0
x2 + 2ix + (-1 + -1i) = 0

Reorder the terms:
-1 + -1i + 2ix + x2 = 0

Solving
-1 + -1i + 2ix + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + -1i + 2ix + 1 + x2 = 0 + 1

Reorder the terms:
-1 + 1 + -1i + 2ix + x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1i + 2ix + x2 = 0 + 1
-1i + 2ix + x2 = 0 + 1

Combine like terms: 0 + 1 = 1
-1i + 2ix + x2 = 1

Add '-1x2' to each side of the equation.
-1i + 2ix + x2 + -1x2 = 1 + -1x2

Combine like terms: x2 + -1x2 = 0
-1i + 2ix + 0 = 1 + -1x2
-1i + 2ix = 1 + -1x2

Reorder the terms:
-1 + -1i + 2ix + x2 = 1 + -1x2 + -1 + x2

Reorder the terms:
-1 + -1i + 2ix + x2 = 1 + -1 + -1x2 + x2

Combine like terms: 1 + -1 = 0
-1 + -1i + 2ix + x2 = 0 + -1x2 + x2
-1 + -1i + 2ix + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
-1 + -1i + 2ix + x2 = 0

The solution to this equation could not be determined.

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